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  4. The collector current in a common base amplifier using n-p-n transistor is 24 mA. If 80 % of the electrons released by the emitter is accepted by the collector, then the base current is numerically:

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Q. The collector current in a common base amplifier using $n-p-n$ transistor is $24\, mA$. If $80 \%$ of the electrons released by the emitter is accepted by the collector, then the base current is numerically:

NEETNEET 2022Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

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$I _{ C }=24 \,mA$
and $I _{ E }=\frac{ I _{ C }}{\alpha}$
$ I _{ E }=\frac{24 mA }{0.8}=30 \,mA $
$\therefore I _{ B }= I _{ E }- I _{ C }$
$=6\, mA$ (into the base)