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Q. The coercivity of a small bar magnet is $4\times 10^{3} \, A \, m^{- 1}$ . It is inserted inside a solenoid of $500$ turns and length $1 \, m$ to demagnetize it. The amount of current to be passed through the solenoid will be

NTA AbhyasNTA Abhyas 2022

Solution:

$n$ = number of turns per unit length of solenoid ,
$n=\frac{500}{1}$
$H=ni\Rightarrow i=\frac{H}{n}=\frac{4 \times 10^{3}}{500}=8 \, A$