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Q. The coercive force for certain permanent magnet is $2\times 10^{4}Am^{- 1}$ . This magnet is placed inside a Iong solenoid of $40$ turns $cm^{- 1}$ and a current is passed in the solenoid to demagnetize the magnet. The value of current (in $A$ ) is

NTA AbhyasNTA Abhyas 2022

Solution:

$H=B/\mu _{0}$
$ni=2\times 10^{4}$
$40\times 100i=2\times 10^{4}$
$I=\frac{20}{4}A=5A$