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Q.
The coefficients of mutual inductance when magnetic flux changes by $2 \times 10^{-2} Wb$ and current changes by $0.01\,A,$ will be
Electromagnetic Induction
Solution:
Coefficient of mutual induction of two coils is equal to the number of magnetic flux $(\phi)$ linkages in one coil when a unit current $(i)$ flows in the other.
Therefore, $M=\frac{\phi}{i}$
Given, $\phi=2 \times 10^{-2} Wb , i=0.01\, A$
$\therefore M=\frac{2 \times 10^{-2}}{0.1}=2\, H$