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Q. The coefficient self inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will becomes

CMC MedicalCMC Medical 2012

Solution:

We know that, $ L=\mu ni $ $ \therefore $ $ \frac{{{L}_{2}}}{{{L}_{1}}}=\frac{\mu }{{{\mu }_{0}}} $ (as n and i are same) $ \Rightarrow $ $ {{L}_{2}}=\frac{\mu }{{{\mu }_{0}}}\times {{L}_{1}}={{\mu }_{r}}{{L}_{1}} $ $ =900\times 0.18=162\text{ }mH $