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Mathematics
The coefficient of x2 in the expansion of the product (2-x2)⋅((1+2x+3x2)6 + (1-4x2)6) is :
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Q. The coefficient of $x^2$ in the expansion of the product $(2-x^2)⋅((1+2x+3x^2)^6 + (1-4x^2)^6)$ is :
JEE Main
JEE Main 2018
Binomial Theorem
A
107
16%
B
106
45%
C
108
29%
D
155
10%
Solution:
coefficient of $ x^2=2 $ coefficient of $x^2 \text { in } $
$ \left(\left(1+2 x+3 x^2\right)^6+\left(1-4 x^2\right) 6\right) $ - constant term
$ \left(1+2 x+3 x^2\right) 6 \displaystyle\sum_{r=0}^6 $
$ { }^6 C_r\left(2 x+3 x^2\right)^r $
$ ={ }^6 C_0+{ }^6 C_1\left(2 x+3 x^2\right)+{ }^6 C_2\left(2 x+3 x^2\right)^2+\ldots $
coefficient of $ x^2=2(18+60-24)-2 $
$ =108-2=106$