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Q. The coefficient of volumetric expansion of mercury is $18 \times 10^{-50} C ^{-1}$. The thermometer bulb has a volume of $10^{-6} \cdot m ^{3}$ and cross-section of the stem is $0.002 cm ^{2}$. Assuming that bulb is filled with mercury at $0^{\circ} C$, the increase in length of the mercury column at $100^{\circ} C$ will be

Thermal Properties of Matter

Solution:

The increase in the length of mercury column is
$\Delta L_{ Hg } =\frac{\gamma_{ Hg } V \Delta T}{A}$
$=\frac{\left(18 \times 10^{-5}\,{}^{{\circ}} C ^{-1}\right)\left(10^{-6} m ^{3}\right)\left(100^{\circ} C \right)}{\left(0.002 \times 10^{-4} m ^{2}\right)} $
$=9 \times 10^{-2} m =9 \,cm$