Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The coefficient of thermal expansion, $\alpha$, is nearly constant for a liquid $\alpha=\frac{1}{V}\left(\frac{dV}{dT}\right)_{P}$
At $293 K$ and $1 atm$ for water $\alpha = 2.1 K^{-1}$ What is the approximate work done when $1$ mole of liquid is heated from $288 K$ to $298 K$ at $1 atm$ ? Molar volume of liquid $= 18 ml?$

Thermodynamics

Solution:

$dV=\alpha VdT$
$\Delta W=-\int PdV=-\alpha V\times P \int_{T_1}^{T_{2}} dT$
or $\Delta W=-2.1\times18\times10^{-6}\times10^{5}\times10 J$
or $\Delta W=-2.1\times18\, J$
or $\Delta W=-37.8\, J$