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Q. The coefficient of thermal conductivity of copper is $9$ times that of steel. In the composite cylindrical bar shown in the figure, what will be the temperature at the junction of copper and steel?
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NTA AbhyasNTA Abhyas 2022

Solution:

Temperature of the interface,
$\theta =\frac{K_{1} \theta _{1} l_{2} + K_{2} \theta _{2} l_{1}}{K_{1} l_{2} + K_{2} l_{1}}$
It is given that $K_{Cu}=9K_{s}$ . So, if $K_{s}=K_{1}=K$ , then
$K_{Cu}=K_{2}=9K$
$\Rightarrow $ $\theta =\frac{9 K \times 100 \times 6 + K \times 0 \times 18}{9 K \times 6 + K \times 18}$
$ \, =\frac{5400 K}{72 K}=75^\circ C$