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  4. The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2 . The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be N. [ g =10 ms -2]

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Q. The coefficient of static friction between a wooden block of mass $0.5 kg$ and a vertical rough wall is 0.2 . The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be ________N. $\left[ g =10 ms ^{-2}\right]$

JEE MainJEE Main 2021Laws of Motion

Solution:

F.B.D. of the block is shown in the diagram
image
Since block is at rest therefore
$fr - mg =0 \dots$(1)
$F-N=0 \dots$(2)
$fr \leq \mu N$
In limiting case $fr =\mu N =\mu F \dots$(3)
Using eq. (1) and (3)
$\therefore \mu F=m g$
$\Rightarrow F =\frac{0.5 \times 10}{0.2}=25 N$