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Q. The coefficient of self induction of two inductor coils are $20\, mH$ and $40\, mH$ respectively. If the coils are connected in series so as to support each other and the resultant inductance is $80 \,mH$ then the value of mutual inductance between the coils will be

Electromagnetic Induction

Solution:

$L_{1}=20 \,mH , L_{2}=40\, mH$
$L=L_{1}+L_{2} \pm 2\, M$
$80=20+40+2 \,M$
$M =10 \,mH$