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Q.
The coefficient of mean deviation from median of
observations $40, 62, 54, 90, 68, 76$ is :-
Statistics
Solution:
Arrange the given observations in ascending order $40,54,62,68,76,90$
no. of terms $( n )=6$ (even)
$\therefore $ Median (M)
$=\frac{\left(\frac{ n }{2}\right) \text { th term }+\left(\frac{ n }{2}+1\right) \text { th term }}{2}=\frac{62+68}{2}=65$
$\Sigma\left| x _1- M \right|=25+11+3+3+11+25=78$
M.D. from median $=\frac{\Sigma\left| x _1- M \right|}{ n }=\frac{78}{6}=13$
$\therefore$ Coefficient of M.D. $=\frac{\text { M.D. }}{\text { median }}=\frac{13}{65}=0.2$