Thank you for reporting, we will resolve it shortly
Q.
The coefficient of friction between two surfaces is $\mu =0.8.$ The tension in the string as shown in the figure is
NTA AbhyasNTA Abhyas 2022
Solution:
maximum friction force
$f_{max} = \mu N$
$=\mu mgcos 30^\circ $
$=0.8\times 1\times 10\times \frac{\sqrt{3}}{2}$
$=4\sqrt{3}$
$=6.92 \, N$
And $mgsin 30^\circ =1\times 10\times \frac{1}{2}\text{ = }5N$
Also $T+f=mgsin 30^\circ $
Since, the frictional force is more as compare to force $\left(m g s i n 30 ^\circ \right)$ i.e., $6.92 \, N>5 \, N.$
Therefore, the tension in the string would be zero. No motion will take place.
