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Q. The coagulation power of electrolyte ' $X$ ' is ___ times greater than that of electrolyte ' $Y$ '. The coagulation values of $X$ and $Y$ are $30$ and $138$ respectively.

Surface Chemistry

Solution:

Coagulation power is inversely proportional to the coagulation value. Therefore, the ratio of coagulation power is:
$\frac{\text { Coagulation power of } X}{\text { Coagulation power of } Y}=\frac{\text { Coagulation value of } Y}{\text { Coagulation value of } X}$
$=\frac{138}{30}$
$=4.6$
$\therefore X$ has $4.6$ times greater coagulation power than $Y$.