Question

The co-ordinate of a point on the auxiliary circle of the ellipse $x^{2}+2 y^{2}=4$ corresponding to the point on the ellipse whose eccentric angle is $60^{\circ}$ will be

• A. $(\sqrt{3}, 1)$
• B. $(1, \sqrt{3})$
• C. $(1,1)$
• D. $(1,2)$

Answer 1

Answer: (B)

$\frac{x^{2}}{4}+\frac{y^{2}}{2}=1$
Equation of auxiliary circle is
$x^{2}+y^{2}=4$
$\therefore $ Point on the auxiliary circle is
$p\left(2 \cos 60^{\circ}, 2 \sin 60^{\circ}\right)$
$p(1, \sqrt{3})$