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Q. The circular scale of a screw gauge has $50$ divisions and pitch of $0.5\, mm$. Find the diameter of sphere. Main scale reading is $2$.Physics Question Image

IIT JEEIIT JEE 2006Physical World, Units and Measurements

Solution:

Least count (LC) $= \frac {\text{Pitch}}{\text{Number of divisions on circular scale }}$
$ = \frac {0.5}{50}=0.01 \, mm $
Now, diameter of ball
$ = (2 \times 0.5 \, mm)+(25-5)(0.01)=1.2 \, mm $