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  4. The circular divisions of shown screw gauge are 50 . It moves 0.5 mm on main scale in one rotation. The diameter of the ball is

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Q. The circular divisions of shown screw gauge are $50$ . It moves $0.5 \,mm$ on main scale in one rotation. The diameter of the ball is

JEE AdvancedJEE Advanced 2006

Solution:

Since zero of the main scale coincides with the fifth division of the circular scale,
we have the zero error as
$5 \times \frac{0.05}{50}=0.05\, mm$
image
The actual measured (see the figure shown here) reading gives
$(2 \times 0.5) mm +\left(25 \times \frac{0.5}{50}\right) mm -0.05 \,mm$
$=(1+0.25-0.05) mm =1.20 \,mm$