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Q. The circuit shown in the figure contains two diodes each with a forward resistance of $30 \,\Omega$ and with infinite backward resistance. If the battery is $3\, V$, the current through the $50 \,\Omega$ resistance (in ampere) is
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Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

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In the circuit the upper diode $D_1$ is reverse biased and the lower diode $D_2$ is forward biased. Thus there will be no current across upper diode junction. The effective circuit will be as shown in figure.
Total resistance of circuit,
$R = 50 + 70 + 30 = 150 \,\Omega$
Current in circuit,
$I = \frac{V}{R}$
$= \frac{3 V}{150 \Omega} $
$ = 0.02 \,A$