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Q. The circle passing through the point $(-1,0)$ and touching the $y$-axis at $(0,2)$ also passes through the point

JEE AdvancedJEE Advanced 2011Conic Sections

Solution:

Circle touching $y$-axis at $(0,2)$ is $( x -0)^{2}+( y -2)^{2}+\lambda x =0$
passes through $(-1,0)$
$\therefore 1+4-\lambda=0 \Rightarrow \lambda=5$
$\therefore x^{2}+y^{2}+5 x-4 y+4=0$
Put $y =0 \Rightarrow x =-1,-4$
$\therefore $ Circle passes through $(-4,0)$