Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The charring product formed when C6H12O6 is heated with conc. H2SO4 is due to:
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The charring product formed when $C_6H_{12}O_6$ is heated with conc. $H_2SO_4$ is due to:
Biomolecules
A
oxidation
B
reduction
C
dehydration
D
dehydrogenation
Solution:
Glucose $\xrightarrow{conc. H_2SO_4} 6C + 6H_2O;$ this is dehydration.