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Q. The charge required to liberate 11 .5 g sodium from fused sodium chloride is

Electrochemistry

Solution:

For $23 \,g\, Na$, charge required $= 1$ Faraday
For $11 .5 \,g\, Na$, charge required
$ =\frac{1}{23} \times 11.5 $
$= 0.5$ Faraday