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Chemistry
The charge required to liberate 11 .5 g sodium from fused sodium chloride is
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Q. The charge required to liberate 11 .5 g sodium from fused sodium chloride is
Electrochemistry
A
0.5 Faraday
50%
B
1.0 Faraday
29%
C
1.5 Faraday
7%
D
96500 Coulomb
14%
Solution:
For $23 \,g\, Na$, charge required $= 1$ Faraday
For $11 .5 \,g\, Na$, charge required
$ =\frac{1}{23} \times 11.5 $
$= 0.5$ Faraday