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Chemistry
The charge required for the reduction of 1 mol of MnO4- to MnO2 is
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Q. The charge required for the reduction of $1$ mol of $MnO_4^-$ to $MnO_2$ is
KCET
KCET 2018
Electrochemistry
A
1 F
21%
B
3 F
51%
C
5 F
17%
D
6 F
10%
Solution:
$MnO _{4}^{-}+2 H _{2} O +3 e ^{-} \longrightarrow MnO _{2}+4 OH ^{-}$
In the above reduction requires flow of $3$ moles of electrons. So it required $3 F$ charge.