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Q. The charge required for the reduction of $1$ mol of $MnO_4^-$ to $MnO_2$ is

KCETKCET 2018Electrochemistry

Solution:

$MnO _{4}^{-}+2 H _{2} O +3 e ^{-} \longrightarrow MnO _{2}+4 OH ^{-}$
In the above reduction requires flow of $3$ moles of electrons. So it required $3 F$ charge.