Let in $[Ni(C0)_4]$, oxidation state (charge) of Ni is x.
$\, \, \, \, \, \, \, \, \, \, \, \, \, Ni(CO)_4$
$\, \, \, \, \, \, \, \, \, \, \, x + (0 \times 4) = 0 [\because$ Oxidation state of CO= O]
$\therefore \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, $x=0
In metal carbonyl, oxidation state of metal is always zero.