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  4. The charge on the 6 μ F capacitor in the circuit shown is

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Q. The charge on the $6 \,\mu F$ capacitor in the circuit shown isPhysics Question Image

Electrostatic Potential and Capacitance

Solution:

image
$\frac{1}{C}=\frac{1}{18}+\frac{1}{9}=\frac{3}{18}$
$C=6 \,\mu F$
$q=6 \times 90=540\, \mu C$
$\frac{q_{1}}{540-q_{1}}=\frac{6}{12}$
$2 q_{1}=540-q_{1}$
$3 q_{1}=540$
$q_{1}=180 \,\mu C$