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  4. The charge on 500 cc of water due to protons will be

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Q. The charge on $500 cc$ of water due to protons will be

Electric Charges and Fields

Solution:

$Q=n e$, where $n=$ number of moles $\times 6.02 \times 10^{23} \times 10$
$\Rightarrow Q=\frac{500}{18} \times 6.02 \times 10^{23} \times 10 \times 1.6 \times 10^{-19} $
$=2.67 \times 10^{7} C$