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Q.
The charge of an electron is $1.6 \times 10^{-19} C$. How many electrons strike the screen of cathode ray tube each second, when the beam current is $16\, mA$ ?
AMUAMU 2000
Solution:
We know that
current $(I)=$ charge $(q) \times$ time $(t)$ ...(i)
Also, time $(t)=\frac{1}{\text { frequency }(n)}$ ...(ii)
From Eqs. (i) and (ii), we get
$n=\frac{q}{I}$
Given, $q=1.6 \times 10^{-19} C$,
$I=16\, mA =16 \times 10^{-3} A$
$n=\frac{1.6 \times 10^{-19}}{16 \times 10^{-3}}=10^{-17}$