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Q. The change of flux is greatest at $\theta$ is equal to (given, $\left.\phi_{B}=N B A \cos \omega t\right)$

Electromagnetic Induction

Solution:

$\frac{d \phi_{B}}{d t}=-N B A \omega \sin \omega t$,
change of flux is greatest for
$\omega t=\theta=90^{\circ}, 270^{\circ}, \theta=90^{\circ}, 270^{\circ}$.