Question

The change of energy on vaporizing $ 1.00\, kg $ of liquid water at $ 0^\circ C $ and $ 1\, atm $ is

• A. $ 2367 \,kJ\, kg^{-1} $
• B. $ -2367\, kJ\, kg^{-1}$
• C. $ -2367 \, kJ\, mol^{-1} $
• D. $ -2367\, kJ\,g^{-1} $

Answer 1

Answer: (A)

The change of energy on vaporizing $1.00\, kg$ of any liquid at $0^{\circ}C$ and $1$ atm is called its latent heat of vaporization. For water its value is $2367 \,kJ \,kg^{-1}$.