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Q. The central metal ion is ferric ion in:

Coordination Compounds

Solution:

$K_4[Fe(CN)_{6}] \to [Fe(CN)_{6}^{4-} =x+6(-1) =-4 $

$=x-6=-4$

$=x=-4=6=+2$

$K_4[Fe(CN)_{6}] \to [Fe(CN)_{6}^{3-} =x+6(-1) =-3 $

$=x-6=-3 $

$x=-3+6$

$x=+3$