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  4. The cell potential for Zn | Zn 2+( aq )|| Sn x +| Sn is 0.801 V at 298 K. The reaction quotient for the above reaction is 10-2. The number of electrons involved in the given electrochemical cell reaction is. .... (Given E Zn 2+ mid Zn 0=-0.763 V, E Sn x + mid sn 0=+0.008 V and .(2.303 RT / F )=0.06 V )

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Q. The cell potential for $Zn \left| Zn ^{2+}( aq )\right|\left| Sn ^{ x +}\right| Sn$ is $0.801 \,V$ at $298\, K$. The reaction quotient for the above reaction is $10^{-2}$. The number of electrons involved in the given electrochemical cell reaction is. ....
(Given $E _{ Zn ^{2+} \mid Zn }^0=-0.763\, V$,
$E _{ Sn ^{ x +} \mid sn }^0=+0.008 \,V$ and
$\left.\frac{2.303 RT }{ F }=0.06 \,V \right)$

JEE MainJEE Main 2022Electrochemistry

Solution:

$ E = E ^0-\frac{2.303 RT }{ nF } \log Q$
Here, $ E =+0.801 \,V , E ^0=0.008-(-0.763) $
$=+0.771\, V $
$ \therefore 0.801=+0.771-\frac{0.06}{ n } \log 10^{-2} $
$ \Rightarrow n =4$