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Q. The cartesian form of the polar equation $\theta=\tan ^{-1} 2$ is

EAMCETEAMCET 2005

Solution:

Given that
image
$ \theta=\tan ^{-1} 2 $
$ \Rightarrow \tan \theta=2 $
We know, $x= r \cos \theta, $
$y=r \sin \theta $
$ \Rightarrow \tan \theta=\frac{y}{x} $
$ \therefore y=2 x$