1. Tardigrade
  2. Question
  3. Physics
  4. The capacity and the energy stored in a parallel plate condenser with air between its plates are respectively C0 and W0 . If the air is replaced by glass (dielectric constant =5 ) between the plates, the capacity of the plates and the energy stored in it will respectively be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The capacity and the energy stored in a parallel plate condenser with air between its plates are respectively $C_{0}$ and $W_{0} .$ If the air is replaced by glass (dielectric constant $=5$ ) between the plates, the capacity of the plates and the energy stored in it will respectively be

Electrostatic Potential and Capacitance

Solution:

When a dielectric $K$ is introduced in a parallel plate condenser, its capacity becomes $K$ times.
Hence $C'=5 C_{0}$
Energy stored, $W_{0}=\frac{q^{2}}{2 C_{0}}$
$\therefore W'=\frac{q^{2}}{2 C'}=\frac{q^{2}}{2 \times 5 C_{0}}$
$\Rightarrow W'=\frac{W_{0}}{5}$