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Q. The capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. A potential difference of $500\, volt$ is applied to the outer plates of capacitor system. Then the charge on each capacitor is equal to

Electrostatic Potential and Capacitance

Solution:

Total capacitance, $C_s = \frac{4 \times 6}{4 + 6} \, \mu $F = 2.4 $\mu$F
Charge $q = VC_s = 500 \times 2.4 \times 10^6 $ = 1200 $\mu$C