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Q. The $C-H$ bond distance is the longest in

AFMCAFMC 2009

Solution:

As the $s$-character or number of $\pi$-electrons increases, bond length decreases.
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Therefore, $C _{2} H _{4} Br _{2}$ due to the absence of $\pi$-electrons or due to the presence of lesser $s$-character $(25 \%)$, has the longest $C - H$ bond distance.