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  4. The brown coloured gas is prepared by the action of concentrated nitric acid on copper is an equilibrium mixture of dinitrogen tetraoxide and nitrogen dioxide. mathrmN2 mathrmO4( mathrm~g) leftharpoons 2 mathrmNO2( mathrm~g) Which one of the following changes would result in a darkening of the colour?

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Q. The brown coloured gas is prepared by the action of concentrated nitric acid on copper is an equilibrium mixture of dinitrogen tetraoxide and nitrogen dioxide.

$\mathrm{N}_2 \mathrm{O}_4(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_2(\mathrm{~g})$

Which one of the following changes would result in a darkening of the colour?

NTA AbhyasNTA Abhyas 2020The p-Block Elements - Part2

Solution:

$N_{2}O_{4}\left(\right.g\left.\right)\rightleftharpoons2NO_{2}\left(\right.g\left.\right)$

Here brown colour is formed due to $NO_{2}$ gas. Darkening of colour is possible when more $NO_{2}$ is formed when temperature is increased the equilibrium shifted to the right side as it is an endothermic process.