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Chemistry
The bonds present in borazole (B3N3H6) are
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Q. The bonds present in borazole $(B_3N_3H_6)$ are
The p-Block Elements
A
$ 9 \sigma , 6 \pi $
16%
B
$ 12 \sigma , 3 \pi $
64%
C
$ 6 \sigma , 9 \pi $
16%
D
$ 15 \sigma $ only
4%
Solution:
There are six B-N, three B-H and three N-H sigma bonds and three B-N pi bonds in borazole.