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Q.
The bond order of the N−O bonds in $NO_{3}^{-}$ ion is
NTA AbhyasNTA Abhyas 2022
Solution:
Bond order $=\frac{t o t a l n u m b e r o f b o n d s}{t o t a l r e s o n a t i n g s t r u c t u r e s}=\frac{2 + 1 + 1}{3}=1.33$
$\text{Bond} \, \text{Order} = 1 + \frac{\pi }{\sigma } = 1 + \frac{1}{3} = 1.33$