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  4. The bond order of nitrogen molecule is

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Q. The bond order of nitrogen molecule is

BHUBHU 2007

Solution:

$N _{2}$ molecule, according to MOT,
$\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2},\begin{cases}\pi 2 p_{y}^{2} \\ \pi 2 p_{z}^{2}\end{cases}, \quad \sigma 2 p_{x}^{2}$
Bond order $=\frac{\text {No. of bonding electrons - No of antibonding electrons }}{2} $
$=\frac{10-4}{2}=\frac{6}{2}=3$