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Q.
The bond length the species $O_2, O_2^+$ and $O_2^-$ are in the order of
Chemical Bonding and Molecular Structure
Solution:
As bond order increases bond length decrease, the bond order of species are
$= \frac{\text{Number of bonding electron - Number of antibonding electron}}{2}$
For $O_2 = \frac{1.-6}{2} = 2 ; O_2^+ = \frac{10-5}{2} = 2.5$
$O_2^- = \frac{10-7}{2} = 1.5$
So, bond order $O_2^+ > O_2 >O_2^-$ and bond length are $O_2^+ > O_2 >O_2^-$