Question

The bond length of $HCl$ bond is $2.29 \times 10^{-10}\, m$. The percentage ionic character of $HCl$, if measured dipole moment is $6.226 \times 10^{-30}\, C \,m$ is

• A. 8 %
• B. 20 %
• C. 17 %
• D. 50 %

Answer 1

Answer: (C)

$\mu_{cal} = q \times d = 1.6 \times 10^{-19 } \times 2.29 \times 10^{-10}$.
$ = 3.664 \times 10^{-29}\, C\, m$
% ionic character = $\frac{\mu_{exp}}{\mu_{cal}} \times 100$
$= \frac{6.226 \times 10^{-30}}{3.664 \times 10^{-29}} \times 100 = 17 \%$