1. Tardigrade
  2. Question
  3. Chemistry
  4. The bond length of H2+, H2- and H2 are in the following order

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Q. The bond length of $ H_2^+, H_2^- $ and $ H_2 $ are in the following order

UPSEEUPSEE 2010

Solution:

$H _{2}^{+}(2-1=1)=\sigma 1 s^{1}$

$BO =\frac{1-0}{2}=0.5$

$H _{2}^{-}(2+1=3)=\sigma 1 s^{2}, \overset{*} {{\sigma}} 1 s^{1} $

$BO =\frac{2-1}{2}=0.5$

$H _{2}(2)=\sigma 1 s^{2}$

$BO =\frac{2-0}{2}=1$

$\because$ The order of bond order is

$H _{2}> H _{2}^{+}> H _{2}^{-}$

Thus, the order of bond length is

$H _{2}^{-}> H _{2}^{+}> H _{2}$