Question

The bond formed between carbon atom $1$ and carbon atom $2$ in compound $\underset{1}{C} H_{2}=\underset{2}{C}=\underset{3}{C} H \underset{4}{C} H_{3}$ involves the hybrids as:

• A. $ sp $ and $ sp $
• B. $ sp^{3} $ and $ sp $
• C. $ sp^{2} $ and $ sp $
• D. $ sp $ and $ sp^{2}$

Answer 1

Answer: (C)

Note: $-C-C s p^{3}-C=C-s p^{2}=C=C=s p-C \equiv C s p$
$\overset{1}{\underset{s p^{2}}{ CH _{2}}}=\overset{2}{\underset{s p}{ C }}=\overset{3}{\underset{s p^{2}}{ CH }}-\overset{4}{\underset{s p^{3}}{ CH _{3}}}$