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  4. The boiling point of n-heptane is 36°C . What will be its molar heat of vaporisation?

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Q. The boiling point of $n$-heptane is $ 36^{\circ}C $ . What will be its molar heat of vaporisation?

Haryana PMTHaryana PMT 2005

Solution:

According to Troutons law, $\frac{\Delta H_{p}}{T_{b}}=88 \,JK ^{-1} mol ^{-1} $
$\therefore $ $\Delta H_{v}=88 \times 309$
$=27192 \,J \,mol ^{-1}$