1. Tardigrade
  2. Question
  3. Chemistry
  4. The boiling point (in ° C ) of 0.1 molal aqueous solution of CuSO 4 .5 H 2 O at 1 bar is closest to: [Given: Ebullioscopic (molal boiling point elevation) constant of water, .K b =0.512 K Kg mol -1]:-

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Q. The boiling point (in ${ }^{\circ} C$ ) of $0.1$ molal aqueous solution of $CuSO _{4} .5 H _{2} O$ at $1$ bar is closest to: [Given: Ebullioscopic (molal boiling point elevation) constant of water, $\left.K _{ b }=0.512 \,K \,Kg\, mol ^{-1}\right]:-$

KVPYKVPY 2020

Solution:

$CuSO_4 \cdot 5H_2O \ce{->[H_2O]} Cu^{2\oplus} + SO_4^{2\ominus}$
$i = 2$
$\Delta T_b = i . K_b . m = 2 \times 0.512 \times 0.1 = 0.1024$
$T_b' = T_b ^0 + \Delta T_b = 100 + 0.1024 = 100.10$