1. Tardigrade
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  3. Physics
  4. The bob of a simple pendulum of mass m and length ; is droped from the horizontal position strikes a block of the same mass elastically placed on a horizontal frictionless table. The kinetic energy of the block will be

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Q. The bob of a simple pendulum of mass m and length ; is droped from the horizontal position strikes a block of the same mass elastically placed on a horizontal frictionless table. The kinetic energy of the block will be

CMC MedicalCMC Medical 2012

Solution:

The given condition can be shown as
Potential energy of bob at point $ A=mgl $ The total energy is converted into kinetic energy. $ \therefore $ Kinetic energy of bob at point B $ =mgl $ As collision between bob and block is elastic so after collision bob will come to rest and total kinetic energy will be transferred to block. So, kinetic energy of the block = mgl

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