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  4. The bob of a simple pendulum has mass 2g and a charge of 5.0 μ C. It is at rest in a uniform horizontal electric field of intensity 2000 V/m. At equilibrium, the angle that the pendulum makes with the vertical is: (take g = 10 m/s2)

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Q. The bob of a simple pendulum has mass $2g$ and a charge of $5.0\, \mu C$. It is at rest in a uniform horizontal electric field of intensity $2000\, V/m$.
At equilibrium, the angle that the pendulum makes with the vertical is : (take $g\, =\, 10 \,m/s^2$)

JEE MainJEE Main 2019Electric Charges and Fields

Solution:

$\tan \theta = \frac{qE}{mg} = \frac{5\times10^{-6} \times2000}{2\times10^{-3} \times10}$
$ \tan\theta = \frac{1}{2} \Rightarrow \theta = \tan^{-1} \left(0.5\right) $

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