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  4. The binding energy per nucleon of 37 Li and 24 He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction 37 Li + 11 H arrow 2 24 He +Q, the value of energy Q (in MeV ) released is

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Q. The binding energy per nucleon of ${ }_{3}^{7} Li$ and ${ }_{2}^{4} He$ nuclei are $5.60\, MeV$ and $7.06\, MeV$, respectively. In the nuclear reaction ${ }_{3}^{7} Li +{ }_{1}^{1} H \rightarrow 2{ }_{2}^{4} He +Q$, the value of energy $Q$ (in $MeV$ ) released is

Nuclei

Solution:

BE of ${ }_{2} He ^{4}=4 \times 7.06=28.24\, MeV$
$BE$ of ${ }_{3}^{7} Li =7 \times 5.60=39.20\, MeV$
$\underset{39.20}{{ }_{3}^{7} Li} +{ }_{1}^{1} H \longrightarrow \underset{28.24\times2}{{ }_{2} He ^{4}}+{ }_{2} He ^{4}+Q$
$Q=56.48-39.20=17.28\, MeV$