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Q.
The binding energy per nucleon for deuteron $(_1H^2)$ and helium $(_2He^4)$ are $1.1\, MeV$ and $7.0\, MeV$ respectively. The energy released when two deuterons fuse to form a helium nucleus is
The nuclear reaction is,
${ }_{1} H ^{2}+{ }_{1} H ^{2} \longrightarrow { }_{2} He ^{4}+Q$
Total binding energy of helium nucleus
$=4 \times 7=28\, MeV$
Total binding energy of each deuteron
$=2 \times 1.1=2.2\, MeV$
Hence, energy released when two deuteron fuse to form helium,
$=28-2 \times 2.2=28-4.4=23.6\, MeV$