1. Tardigrade
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  3. Chemistry
  4. The binding energy of an electron in the ground state of the He atom is equal to 24 eV. The energy required to remove both the electrons from the atom will be:

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Q. The binding energy of an electron in the ground state of the He atom is equal to $24 \,eV$. The energy required to remove both the electrons from the atom will be:

Structure of Atom

Solution:

Ionization energy of $He$

$=\frac{z^{2}}{n^{2}} \times 13.6$

$=\frac{2^{2}}{1^{2}} \times 13.6$

$=54.4\, eV$

Energy required to remove both the electrons

$=$ binding energy + ionisation energy

$= 24.6 + 54.4 = 79\,eV$