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Q. The battery of a trunk has an emf of $24 \,V$. If the internal resistance of the battery is $0.8 \,\Omega$. What is the maximum current that can be drawn from the battery ?

Current Electricity

Solution:

Here, $\varepsilon=24\,V$ and $r=0.8\,\Omega$
For the maximum current from the battery.
$\varepsilon=Ir\quad\left(\because R=0\right)$
$\therefore I=\frac{\varepsilon}{r}=\frac{24}{0.8}=30\,A$